(5v^2-20v-160)/(v^2-3v-28)

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Solution for (5v^2-20v-160)/(v^2-3v-28) equation: 


D( v )

v^2-(3*v)-28 = 0

v^2-(3*v)-28 = 0

v^2-(3*v)-28 = 0

v^2-3*v-28 = 0

v^2-3*v-28 = 0

DELTA = (-3)^2-(-28*1*4)

DELTA = 121

DELTA > 0

v = (121^(1/2)+3)/(1*2) or v = (3-121^(1/2))/(1*2)

v = 7 or v = -4

v in (-oo:-4) U (-4:7) U (7:+oo)

(5*v^2-(20*v)-160)/(v^2-(3*v)-28) = 0

(5*v^2-20*v-160)/(v^2-3*v-28) = 0

5*v^2-20*v-160 = 0

5*(v^2-4*v-32) = 0

v^2-4*v-32 = 0

DELTA = (-4)^2-(-32*1*4)

DELTA = 144

DELTA > 0

v = (144^(1/2)+4)/(1*2) or v = (4-144^(1/2))/(1*2)

v = 8 or v = -4

5*(v+4)*(v-8) = 0

v^2-3*v-28 = 0

v^2-3*v-28 = 0

DELTA = (-3)^2-(-28*1*4)

DELTA = 121

DELTA > 0

v = (121^(1/2)+3)/(1*2) or v = (3-121^(1/2))/(1*2)

v = 7 or v = -4

(v+4)*(v-7) = 0

(5*(v+4)*(v-8))/((v+4)*(v-7)) = 0

( 5 )

5 = 0

v belongs to the empty set

( v+4 )

v+4 = 0 // - 4

v = -4

( v-8 )

v-8 = 0 // + 8

v = 8

v in { -4} 

v = 8

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